反比例函数难题
1/x-1/y=k/(x-y)(y-x)/xy=k/(x-y)-(x-y)²=kxyx²-2xy+y²=-kxy两边加上4xyx²+2xy+y²=4xy-kxy(x+y)²=(4-k)xyx²-2xy+y²=-kxyx²+y²=(2-k)xy则(x+y)²/(x²+y²)=(4-k)/(2-k)k是常数则(4-k)/(2-k)是常数即(x+y)²和x²+y²相除是常数所以成正比
标签：反比例,难题,函数
2022-10-05 00:46:51 编辑：leo 浏览量：607次
反比例函数难题
1/x-1/y=k/(x-y)(y-x)/xy=k/(x-y)-(x-y)²=kxyx²-2xy+y²=-kxy两边加上4xyx²+2xy+y²=4xy-kxy(x+y)²=(4-k)xyx²-2xy+y²=-kxyx²+y²=(2-k)xy则(x+y)²/(x²+y²)=(4-k)/(2-k)k是常数则(4-k)/(2-k)是常数即(x+y)²和x²+y²相除是常数所以成正比
标签：反比例,难题,函数
